OCR Advanced FSMQ - Additional Maths

(g) Yes, 5 x + 2 y = 3 can be rearranged to give 2 y = −5 x + 3 and this can be divided by 2 to give y = − 5 2  x + 3 2 which is in the form y = mx + c (h) Yes, y = 4 3  x − 2 is in the form y = mx + c 5 The line AB has coordinates of A (−5, 0). If the mid-point of AB has coordinates (0, −2), find the coordinates of B . Answer 5 Let the coordinates of B be ( x , y ). The x -coordinate of the mid-point = x + (−5) 2 The x -coordinate is 0, so 0 = x − 5 2 Solving gives x = 5 The y -coordinate of the mid-point = y + 0 2 The y -coordinate is −2, so −2 =  y + 0 2 Solving gives y = −4 Hence, coordinates of B are (5, −4) 6.6 Finding the gradient and the intercept on the y -axis from the equation of a straight line To find the gradient and intercept on the y -axis, we first need to check that the equation for the straight line is in the form y = mx + c . If the equation isn’t in this format, it needs to be rearranged to put it into this format. Example 6 Find the gradient and intercept on the y -axis for the following straight line graphs. (a) y = 4 x + 7 Comparing this with y = mx + c , the gradient m is 4 and the intercept on the y -axis, c is 7. You need to remember that the general equation for a straight line is y = mx + c . This is GCSE material so you may need to look back. 2 Coordinate geometry 124